Python argparse pass multiple values for argument
Given an argument -l, I needed to pass multiple values to it.
python - How can I pass a list as a command-line argument with argparse? - Stack Overflow is an extremely detailed answer with all options, but the TL;DR is:
nargs:
parser.add_argument('-l','--list', nargs='+', help='<Required> Set flag', required=True)
# Use like:
# python arg.py -l 1234 2345 3456 4567
- append:
parser.add_argument('-l','--list', action='append', help='<Required> Set flag', required=True)
# Use like:
# python arg.py -l 1234 -l 2345 -l 3456 -l 4567
Details about values for nargs:
# This is the correct way to handle accepting multiple arguments.
# '+' == 1 or more.
# '*' == 0 or more.
# '?' == 0 or 1.
# An int is an explicit number of arguments to accept.
parser.add_argument('--nargs', nargs='+')
Related, a couple of days ago used nargs to allow an empty value (explicitly passing -o without an argument that becomes a None) while still providing a default value that’s used if -o is omitted completely:
parser.add_argument(
"--output-dir",
"-o",
help="Target directory for the converted .json files. (%(default)s)",
type=Path,
default=DEFAULT_OUTPUT_DIR,
nargs="?",
)
Nel mezzo del deserto posso dire tutto quello che voglio.
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